Equal Sides Of An Array

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You are going to be given an array of integers. Your job is to take that array and find an index N where the sum of the integers to the left of N is equal to the sum of the integers to the right of N. If there is no index that would make this happen, return -1.

For example:

Let's say you are given the array {1,2,3,4,3,2,1}:
Your function will return the index 3, because at the 3rd position of the array, the sum of left side of the index ({1,2,3}) and the sum of the right side of the index ({3,2,1}) both equal 6.

Let's look at another one.
You are given the array {1,100,50,-51,1,1}:
Your function will return the index 1, because at the 1st position of the array, the sum of left side of the index ({1}) and the sum of the right side of the index ({50,-51,1,1}) both equal 1.

Last one:
You are given the array {20,10,-80,10,10,15,35}
At index 0 the left side is {}
The right side is {10,-80,10,10,15,35}
They both are equal to 0 when added. (Empty arrays are equal to 0 in this problem)
Index 0 is the place where the left side and right side are equal.

Note: Please remember that in most programming/scripting languages the index of an array starts at 0.

Input:
An integer array of length 0 < arr < 1000. The numbers in the array can be any integer positive or negative.

Output:
The lowest index N where the side to the left of N is equal to the side to the right of N. If you do not find an index that fits these rules, then you will return -1.

 

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Code:

 

static int findEvenIndex(int[] arr)

     {

        

         int sum=0;

         int count=0;

         int right=0;

         for(int i=0;i<arr.length;i++)

         {

               sum += arr[i];

         }

         for(int i=0;i<arr.length;i++)

         {

              right+=arr[i];

              if(i>0)

              {

              count+=arr[i-1];

             

              System.out.println(count+" "+(sum-right));

              if(count==(sum-right))

              {

                  return i;

              }

              }

              else if(sum-arr[0]==0)

                  return 0;

         }

        

         return -1;

     }